已知字符串s='1234',则表达式 str(s.index('3')+s.count('34'))*len(s) 的值为()。
Option Explicit
Private Sub Command1_Click()
Dim s As String,k As Integer
Dim rAs String,i As Integer,tAs String
s=“aa11bb22Cc33”
For i=1 To Len(s)
t=()
Ift >=“a”And t<=“z”Or t >=“A”And t<=“Z”Then
r=r & t
End If
Next i
Print r
End Sub
Private Sub Command1_Click() Dim y As String,S As String S=Text1.Text 【 】 TextText=y End Sub Private Sub Rever(S As String,y As String) Dim i As Integer y=" " For i=Len(S) To 1 Step-1 y=y&【 】 Next i End Sub