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设f(x)在[a,b]上连续,且f(x)>0 F(x)=∫(上限为x,下限为a)f(t)dt+∫(上限为x,下限为b)1/f(t)dt,x∈[a,b].证明:方程F(x)=0在区间[a,b
设f(x)在[a,b]上连续,且f(x)>0
F(x)=∫(上限为x,下限为a)f(t)dt+∫(上限为x,下限为b)1/f(t)dt,x∈[a,b].证明:方程F(x)=0在区间[a,b]有且仅有一个根.
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设f(x)在[a,b]上连续,且f(x)>0
F(x)=∫(上限为x,下限为a)f(t)dt+∫(上限为x,下限为b)1/f(t)dt,x∈[a,b].证明:方程F(x)=0在区间[a,b]有且仅有一个根.